From c9d72897df5ab09f50164aa856fad841bc90833e Mon Sep 17 00:00:00 2001 From: Christian Kroll Date: Tue, 12 Jan 2016 19:31:14 +0100 Subject: [PATCH] Vorwiderstandsfolien --- Vorträge/arduino/.gitignore | 4 +- Vorträge/arduino/bilder/ohm_dreieck.pdf | Bin 0 -> 4828 bytes Vorträge/arduino/bilder/vorwiderstand.pdf | Bin 0 -> 9976 bytes Vorträge/arduino/bilder/widerstaende.pdf | Bin 0 -> 8474 bytes Vorträge/arduino/kapitel/led_auf_shield.tex | 73 +++++++++++++++++++- 5 files changed, 74 insertions(+), 3 deletions(-) create mode 100644 Vorträge/arduino/bilder/ohm_dreieck.pdf create mode 100644 Vorträge/arduino/bilder/vorwiderstand.pdf create mode 100644 Vorträge/arduino/bilder/widerstaende.pdf diff --git a/Vorträge/arduino/.gitignore b/Vorträge/arduino/.gitignore index c8fdc81..475684c 100644 --- a/Vorträge/arduino/.gitignore +++ b/Vorträge/arduino/.gitignore @@ -4,7 +4,9 @@ *.log *.nav *.out -*.pdf *.snm *.swp *.toc +arduino.synctex.gz +arduino.vrb +arduino.pdf diff --git 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a/Vorträge/arduino/kapitel/led_auf_shield.tex +++ b/Vorträge/arduino/kapitel/led_auf_shield.tex @@ -69,12 +69,81 @@ \end{frame} \begin{frame} - \frametitle{Aufgabe 2: Das Shield, LED Vorwiderstand} + \frametitle{Aufgabe 2: Grundbegriffe} \begin{itemize} - \item %TODO: Hier Vorwiderstand und Ohm erklären + \item \emph{Strom} bezeichnet die Bewegung von geladenen Teilchen + \item \emph{Spannung} ist ein Ladungsunterschied zwischen zwei Orten + \item bewegliche Ladungen wollen Ladungsunterschiede immer ausgleichen $\rightarrow$ Strom fließt + \item der \emph{Widerstand} begrenzt den Stromfluss, alle Verbraucher (wie LEDs) bilden selbst einen Widerstand \end{itemize} \end{frame} + +\begin{frame} + \frametitle{Aufgabe 2: LED anschließen} + \begin{itemize} + \item die LED wird zwischen einem Pin des Controllers und der Masse (Rückleitung) angeschlossen + \item die Spannung zwischen Mikrocontroller und der Masse beträgt 5V + \item \alert{Problem: 5V sind zu viel für eine LED} + \item Lösung: wir brauchen einen Vorwiderstand + \end{itemize} +\end{frame} + +\begin{frame} + \frametitle{Aufgabe 2: Vorwiderstand bestimmen} + \begin{itemize} + \item bei mehreren Widerständen in einem Strang teilt sich die angelegte Spannung im Verhältnis der Widerstände auf die Verbraucher auf + \begin{center} + \includegraphics[width=0.5\linewidth,height=\textheight,keepaspectratio]{bilder/widerstaende.pdf} + \end{center} + \item kennen wir den Widerstand der LED, können wir den Vorwiderstand ausrechnen + \end{itemize} +\end{frame} + +\renewcommand{\arraystretch}{1.5} + +\begin{frame} + \frametitle[fragile]{Aufgabe 2: Ohmsches Gesetz} + \begin{itemize} + \item bei den LEDs sind folgende Angaben wichtig + \begin{itemize} + \item Flussspannung oder Forward Voltage $U_F$, meistens um die 2V + \item Diffusionsstrom oder Forward Current $I_F$, meist um die 20mA $\widehat{=}$ 0,02A + \end{itemize} + \item bei der Berechung hilft uns: + \end{itemize} + \begin{block}{Ohmsches Gesetz} + \begin{columns}[T] + \column{.50\textwidth} + {\Large\begin{tabular}{lc} + Spannung U: & $U = R \cdot I$ \\ + Strom I: & $I = \frac{U}{R}$ \\ + Widerstand R: & $R = \frac{U}{I}$ \\ + \end{tabular}} + \column{.50\textwidth} + \begin{center} + \includegraphics[width=0.4\linewidth,height=\textheight,keepaspectratio]{bilder/ohm_dreieck.pdf} + \end{center} + \end{columns} + \end{block} +\end{frame} + + +\begin{frame} + \frametitle{Aufgabe 2: Vorwiderstand} + \begin{itemize} + \item \LARGE{$R_{Vorwiderstand} = \frac{U_{Betrieb} - U_{F}}{I_F}$} + \item \LARGE setzen wir unsere Werte ein: + \item \LARGE{$R_{Vorwiderstand} = \frac{5V - 2V}{0,02A}$} + \item \LARGE{$R_{Vorwiderstand} = 150\Omega$} + \end{itemize} + \begin{center} + \includegraphics[width=0.4\linewidth,height=\textheight,keepaspectratio]{bilder/vorwiderstand.pdf} + \end{center} + +\end{frame} + + \begin{frame} \frametitle{Aufgabe 2: Das Shield, Verkabelung} \begin{center}